Its behaving like a combinational circuit now, doesnt it I have a core pipeline, which works just fine The output changes immediately with the input now or am i wrong
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It considers that all the variable will be in sensitivity list
So, you don't need to worry about adding them in the sensitivity list.
So, always use always @* or better yet always_comb and forget about the concept of sensitivity lists If the item in the code is evaluated it will trigger the process It an item is in an if/else, a case, assigned to a variable, or anything else, it will be evaluated and thus cause the process to be triggered. The always @(*) syntax was added to the ieee verilog std in 2001
All modern verilog tools (simulators, synthesis, etc.) support this syntax An incomplete event_expression list of an event control is a common source of bugs in register transfer level (rtl) simulations The implicit event_expression, @*, is a convenient shorthand that eliminates these. The always @(*) block is sensitive to change of the values all the variables, that is read by always block or we can say which are at the right side inside the always block
In your example, there are no any variables used inside always block, so this always @(*) block will not work here
As per sv lrm, always_comb is sensitive to changes within the contents of a function, whereas always @* is. The always block must reach the end before any changes are seen outside of the block Paul s is right that you want to always assign something to your variables whenever the always block is executed, otherwise you will infer memory. Is there a difference between an always block, and an always @* block?
I am totally confused among these 4 terms Always_ff, always_comb, always_latch and always How and for what purpose can these be used? Always causes the step to always execute, and returns true, even when canceled
A job or step will not run when a critical failure prevents the task from running
For example, if getting sources failed Which means the job will run even when it gets cancelled, if that's what you want, then go ahead. Imagine assign as wires and always blocks as registers (for now) , as their behavior is same. I am interested in why this always() condition is not behaving as expected in a github workflow
