Therefore, the sum of the areas of the two squares can be expressed as Area of square = s² difference of their perimeters = 8 cm The perimeter of a square is given by the formula p =4s
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Thus, the difference of the perimeters can be expressed as
P 1−p 2 = 4a−4b= 8
The sum of the areas of two squares is 52cm^2 and difference of their perimeters is 8 cm Find the lengths of the sides of the two squares The lengths of the sides of the two squares are 6 cm and 4 cm Let's denote the side length of the first square as 'a' cm and the side length of the second square as 'b' cm.
The sum of the areas of two squares is 52 cm² and difference of their perimeters is 8 cm Find the lengths of the sides of the two. To find the measures of the sides of the two squares, we need to use the given information about the sum of their areas and the product of their perimeters We can set up equations based on these conditions and solve for the side lengths.
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The sum of the areas of two squares is 400 sq.m If the difference between their perimeters is 16 m, find the sides of two squares. Sides of 2 squares solution Sum of areas of 2 squares = 514 cm²
